How to do an equitable random ?


rand gives [0-1], or [0-1[ or ]0-1] or [0-1[ ?

i think its [0-1]

( 6] = 6 include, 6[ = 6 exclude )


Now if I want a rand that returns a int
between 0 and x-1

ex : x=5
i want 0-1-2-3- or 4

i= will be the array indice.

what the correct formule ?

i=x*rand ?

if i do this, i my experience was good, i could get x, so you can have an ArrayOutOfBound

i=(x-1)*rand ?

same, you only get i=x-1 if rand gives 1 => 1/100 chance ?


because i=int/rand=flex and i dont know how to trunc/assign correctly...

[This message has been edited by TCNF_Merfolk (edited November 10, 2002).]

I also think it's a [0 - 1] interval. You can have a simple if(i == 5) check after the computation to make sure it does not get out of bounds...
You can use the flex values as array indices, because cog does automatically convert them using simple truncation. If it does not work nevertheless, do a manual conversion:



------------------
"Häb Pfrässe, süsch chlepfts!" - The coolest language in the world (besides Cherokee)

[This message has been edited by zagibu (edited November 10, 2002).]