Let r(t) = sin(2t)i+cos(t/2)j+sin(t)k

Find the period of r(t). For the life of me, I can't remember how to do it. This is a vector in a three-dimensional space, FYI.

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"LC Tusken: the idiot is the person who follows the idiot and your not following me your insulting me your following the path of a idiot so that makes you the idiot"
NMGOH || Jack Chick preaches it || The Link of the Dead

Ahhhhhh! Vectors! Ahhhhh!!

If you graph it out, the period is one cycle.
For all for sin & cos, one period is 2(Pi).
For sin(2t)i, the period is 2(Pi)
For cos(t/2)j, the period is Pi
For sin(k)k, the period is 2(Pi)

y = Asin(kx+phi) where A = amplitude, k = period change and phi is phase shift of wave.

This help?

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<scribbly handwriting barely resembling name>

Ah, thank you much. Damn trigonometry...

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"LC Tusken: the idiot is the person who follows the idiot and your not following me your insulting me your following the path of a idiot so that makes you the idiot"
NMGOH || Jack Chick preaches it || The Link of the Dead

His period calculations are wrong. The period of sin(2t) is pi, and the period of cos(t/2) is 4*pi.

The period of any function sin(b*x) is (2*pi)/b.