Subject: homework< pre-cal< Trig< 8 identies <help me i forgot math

Algebra really

ok, so were doing this math problems in trig whitch use the fundmental identies and algebra to make one side of the equation look like the other, while keeping everythign equal.

this is done though subustuting the trig functions with there identies and simplifing with basic algebraic principals.

unfortunatlly.... i have forgotten what to do in this sanario:

these are the 8 identies i get to work with:

could someone with a scanner, who knows what i'm talking abotu please help me out with this problem so i can get the general idea abotu how to do this part of algebra. (ie. work the problem out and show steps?) please! i'll give cookies to the person who does!

I'd start by multiplying the equations by the two denominators (basically move the expressions on the bottom of each side up to the top of the other side).

Then replace the csc(theta)s with i/sin(theta)s

Then multiply each side out.

You'll get a whole load of terms that will cancel and you should end up with an equation that looks something like a polynomial. Change the 1/sin to sin^-1 and the 1/(sin^2) to sin^-2 and it'll look even more so (without actually changing the equation :D) If you're lucky you might get to cancel out all the odd powers completely.

Then it's just a case of solving the equation for sin(theta). Then work out what values of theta satisfy those values of sin(theta).

Hopefully that made some sense.

Curse you and your shorthand cosecant!

I'll have a look at it in a bit.

* oh yah * we can only play with one side of the equation
whitch is why i cant to this

or elce i would... unless i dont understand what your saying.

Take the left side,

csc(0) - 1
-----------
csc(0) +1

substitute 1/sin(0) for csc(0):

1/sin(0) - 1
--------------
1/sin(0) +1

Replace the 1s with sin(0)/sin(0):

1/sin(0) - sin(0)/sin(0)
----------------------------
1/sin(0) +sin(0)/sin(0)

factor the 1/sin(0) out of the top and the bottom:

(1-sin(0)) 1/sin(0)
----------- x ---------
(1+sin(0)) 1/sin(0)

1/sin(0)
---------- = 1
1/sin(0)

Therefore, you end up with:

1-sin(0)
----------
1+sin(0)

EDIT: I used "0" instead of theta because there's no theta symbol on my keyboard.

kyle = teh genius

I did the equation despite the fact that the right answer had already been posted.

I am a sad, sad individual.

Kyle gets the cookie!

I did it right before reading the answer, but I also didn't see that you could only use one side

Still solved it

Why thank you, everyone.

*accepts praise graciously*

Yeah, you only have to change something on both sides when you're actually changing it. LIke dividing it, multiplying, adding, etc. With identities, it's just a different way of writing the same thing, you're not actually changing anything. That's why you can work on only one side.

Dammit, I had the solution in mind but kyle already posted it.