Hey, what exactly happens when the following is executed:

main() {
printInt(5 != 5);
printInt(5 == 5);
printInt(5 < 5);
printInt(5 <= 5);
printInt(5 > 5);
printInt(5 >= 5);
printInt(5 != 2);
printInt(5 == 2);
printInt(5 < 2);
printInt(5 <= 2);
printInt(5 > 2);
printInt(5 >= 2);
}

Does it just print out 5 != 5, etc.?

Depends on the compiler.

I don't know for sure but newer versions of C and variants will execute the statements inside the perentheses and return the result, which will be a boolean in this case.

Either that or will error expecting an integer.

EDIT: Looking at your post a second time, appears your getting help with a homework assignment, if thats the case then:

false true false true false true true true false false false true true

would be the output.

It's suppose to be the C-- language.

Not true/false

0
1
0
1
0
1
1
0
0
0
1
1

It'd only print "5 != 5" if the program was made to treat it as outputting a string. printINT, I'm guessing, will simply output the number corresponding to the truth of the statement (I'm assuming).

PrintInt(eger)

Why can't you just run it and find out

Jesus christ bananas I hope you're kidding.

No. Perhaps you're thinking of COG, where -1 is used to determine if no resource is attached to the symbol?

I thought TRUE = 0 and FALSE = -1?

No kidding... it would've ****ing been faster than posting it here

Wolfy is correct, it would print
0
1
0
1
0
1
1
0
0
0
1
1

or
010101100011

He doesn't have the program to run it, possibly.

lol, that's no excuselol!

here you go chap: [url]www.theprogramthatrunsit.com[/url]

enjoiz.

I thought that site was real at the frst glance.....

Yeah, I thought it would be some sort of online compiler or interpreter that would return your data from code heh...poo