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ForumsDiscussion Forum → Angular momentum
Angular momentum
2005-11-19, 1:16 PM #1
My previous thread was closed due to spamming so I am reposting this.

Figure 11-26 shows three particles of the same mass and the same constant speed moving as indicated by the velocity vectors. Points a, b, c, and d form a square, with point e at the center. Rank the points according to the magnitude of the net angular momentum of the three-particle system when measured about the points, greatest first (use only the symbols > or =, for example a>b>c=d=e).

[http://files.upl.silentwhisper.net/upload5/phyprob.GIF]


Okay, so angular momentum is equal to mass (radius cross product velocity). Since velocity is constant and the mass is the same, this leads only the radius or distance to compare. However, I am not quite sure how I should judge the distance of the particles. I mean what is the origin or the reference point that should use to judge these particles from?
2005-11-20, 12:58 AM #2
I think you'd have to just assume the distance between a and b is equal to L, and then use a coefficient to describe the distances between your labelled points a - e and your particles.

For instance taking a as your first reference point, the particle to the left (for argument's sake I'll label them alpha, beta and gamma from left to right), alpha...

Distance alpha to a = pL

where p is a number between 0 and L.

And if you're describing the distance between gamma and c,

Distance = qL

where q is between 0 and L, but less than p.


It might get really confusing, but it's the only way I can see to approach it. I think also the question wants you to do the exercise 5 times, ie finding the angualr momentum of the system around the points a - e in turn, then rank them (if that wasn't clear already).

Gut instinct would tell me that e would probably be origin with the lowest value as everything is going around it, and would therefore have the lowest values of radii.

Good luck!

:D
2005-11-20, 4:23 PM #3
The problem was due last night and I got it wrong....but I'll try to make sense out of it regardless. Thanks Martyn.

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