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☖ Forums → Discussion Forum → Math Question.
Math Question.
2007-01-16, 8:24 PM #1
Rad(y+4) = Rad(y) - 2

I got 0 after squaring both sides...but it seems like I'm doing something wrong. Can someone help me?
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2007-01-16, 8:27 PM #2
or is it no solution.
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2007-01-16, 8:51 PM #3
Quick and dirty in MSPaint.

It works because sqrt(4) = +2,-2

P.S. Jg, didn't you include some math tags which had sqrt working in them?
Attachment: 15128/solution.jpg (24,420 bytes)
Marsz, marsz, Dąbrowski,
Z ziemi włoskiej do Polski,
Za twoim przewodem
Złączym się z narodem.
2007-01-16, 8:51 PM #4
I have never heard of this "Rad" function before.
Stuff
2007-01-16, 8:55 PM #5
Originally posted by kyle90:
I have never heard of this "Rad" function before.


Rad=radical=square root

Though I was confused at first too, thinking he meant radians. Then I thought, what in the world do radians have to do with squaring both sides?
Marsz, marsz, Dąbrowski,
Z ziemi włoskiej do Polski,
Za twoim przewodem
Złączym się z narodem.
2007-01-16, 10:34 PM #6
Never mind I got the solution. There is no solution to this problem.
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2007-01-17, 12:27 AM #7
Originally posted by Warlockmish:
Never mind I got the solution. There is no solution to this problem.

Zero is a solution. No solution means the problem cannot be solved. Something that will come up a lot in linear algebra.

Ric: No. There's no html (last checked) for square root.
Code to the left of him, code to the right of him, code in front of him compil'd and thundered. Programm'd at with shot and $SHELL. Boldly he typed and well. Into the jaws of C. Into the mouth of PERL. Debug'd the 0x258.
2007-01-17, 1:01 AM #8
Originally posted by JediGandalf:
Zero is a solution. No solution means the problem cannot be solved. Something that will come up a lot in linear algebra.

Ric: No. There's no html (last checked) for square root.


Originally posted by W3C:
<!ENTITY radic CDATA "√" -- square root = radical sign,
U+221A ISOtech -->

http://www.w3.org/TR/html401/sgml/entities.html
2007-01-17, 1:03 AM #9
okay, looks like the forums let you specify character codes... if you want the square root symbol, write "&" followed by "#8730;"
√
2007-01-17, 1:07 AM #10
Uhh why don't you try checking the problem? Input 0 in for y and 2 does not equal to negative 2.

People must check their answers.
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2007-01-17, 3:23 AM #11
Originally posted by Ric_Olie:
It works because sqrt(4) = +2,-2

.
Sorry for the lousy German
2007-01-17, 4:45 AM #12
Originally posted by Warlockmish:
Uhh why don't you try checking the problem? Input 0 in for y and 2 does not equal to negative 2.

People must check their answers.


Your calculator will always say √4 equals +2, but it also equals -2. Haven't you learned that stuff in school?
$do || ! $do ; try
try: command not found
Ye Olde Galactic Empire Mission Editor (X-wing, TIE, XvT/BoP, XWA)
2007-01-17, 7:53 AM #13
No, it doesn't. The root symbol designates the principle square root, which is only the positive number. The correct answer is no solution.
2007-01-17, 8:15 AM #14
This is a problem of treating the two sides as functions as opposed to simple systems of equations (my terminology is probably horribly wrong). If you graph the two sides of the equation, they will not intersect because they are functions, but there is a solution to the equation.

Behold my diagram.

Technically, the answer is still no solution, though. (I think)
Attachment: 15131/math1.png (5,345 bytes)
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Nobody really needs work when you have awesome. - xhuxus
2007-01-17, 11:29 AM #15
New tag!
[sqrt]

Usage:[sqrt]3x+5[//sqrt] (of course only one slash)

[sqrt]4x[sup]2[/sup]+7x+8[/sqrt]
Code to the left of him, code to the right of him, code in front of him compil'd and thundered. Programm'd at with shot and $SHELL. Boldly he typed and well. Into the jaws of C. Into the mouth of PERL. Debug'd the 0x258.
2007-01-17, 12:18 PM #16
Spiffy!
一个大西瓜
2007-01-17, 12:54 PM #17
I'll sqrt on you.
2007-01-17, 3:20 PM #18
eww :P
$do || ! $do ; try
try: command not found
Ye Olde Galactic Empire Mission Editor (X-wing, TIE, XvT/BoP, XWA)
2007-01-17, 4:03 PM #19
Originally posted by Vornskr:
No, it doesn't. The root symbol designates the principle square root, which is only the positive number. The correct answer is no solution.

This man has it correct.
2007-01-17, 4:37 PM #20
Right when we begin working with radicals i see this.

Nothing amazing really just nice timing,
2007-01-17, 5:38 PM #21
Originally posted by Vornskr:
No, it doesn't. The root symbol designates the principle square root, which is only the positive number. The correct answer is no solution.


Technically, you're correct, but our professors generally use the root symbol as shorthand, not bothering to put +- in front of it. It depends on how the instructor defines and expects the symbol to be used.
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Z ziemi włoskiej do Polski,
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