I'm working on my math homework, which I put off all day and which is due tomorrow, and I'm stuck on a problem. Normally I'd get help from friends but I procrastinated too much and it's due tomorrow...so I figured I'd see if any of you had any idea. No big deal if you don't, it's only homework. But some of you guys are really good at math, so here it is:
I need to find the indefinite integral of dx/(cos(x)-1)
I really don't know where to go with this one....I've multiplied it all by cos(x)+1 to get (cos(x)^2)-1 on the bottom, which I've turned into -(sin(x)^2), then taken the negative out of the integral, which feels like a step in the right direction MAYBE... but from here I'm just plain stuck. Any ideas?
I need to find the indefinite integral of dx/(cos(x)-1)
I really don't know where to go with this one....I've multiplied it all by cos(x)+1 to get (cos(x)^2)-1 on the bottom, which I've turned into -(sin(x)^2), then taken the negative out of the integral, which feels like a step in the right direction MAYBE... but from here I'm just plain stuck. Any ideas?
Warhead[97]