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☖ Forums → Discussion Forum → It's a frickin laser!!!
It's a frickin laser!!!
2011-05-10, 9:07 AM #1
Just got this in at work!
It is capable of spot welding and emmiting a sustained beam that can cut through 1/4 inch steel.
Probably not really that impressive, but it's still neato!
[http://i30.photobucket.com/albums/c334/darth_alran/59e3a7be.jpg]
[http://i30.photobucket.com/albums/c334/darth_alran/78eff397.jpg]
Welcome to the douchebag club. We'd give you some cookies, but some douche ate all of them. -Rob
2011-05-10, 9:18 AM #2
Coool. How close does the target have to be?
2011-05-10, 9:36 AM #3
It has a maximum range of 1,500 nautical miles.
2011-05-10, 10:39 AM #4
Originally posted by saberopus:
It has a maximum range of 1,500 nautical miles.


Follows curvature of the earth?
Epstein didn't kill himself.
2011-05-10, 1:13 PM #5
uh, have you ever heard of REFRACTION, spook?!?! this is first-grade level science we're talking here
2011-05-10, 2:30 PM #6
No dude, it's the purity of the air that makes a laser curve. (Cus it slows it down)

Duh.
Epstein didn't kill himself.
2011-05-10, 2:36 PM #7
Nah it's cause the curve causes an area of low light pressure. That's why lasers don't work upside down.
nope.
2011-05-10, 2:45 PM #8
I think you mean "laser".
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2011-05-10, 2:56 PM #9
Originally posted by Baconfish:
Nah it's cause the curve causes an area of low light pressure. That's why lasers don't work upside down.


Sort of, it's actually because it has to travel faster over the top of the impurities in the air than across the bottom.
Epstein didn't kill himself.
2011-05-10, 3:06 PM #10
That's not actually necessarily accurate. It's a lot more complicated than that. Part of the reason is that the laser is pushing against the air, not the ground, and this force F is equal to .999999... mv, which is provably the same as F=mv.
Warhead[97]
2011-05-10, 3:16 PM #11
Gist of first post
Originally posted by Darth_Alran:
I gots me a laser!


Gist of the rest of the posts
Originally posted by BobTheMasher:
That's not actually necessarily accurate. It's a lot more complicated than that. Part of the reason is that the laser is pushing against the air, not the ground, and this force F is equal to .999999... mv, which is provably the same as F=mv.


Yep, I'm in massassi!
You can't judge a book by it's file size
2011-05-10, 4:25 PM #12
The most exciting thing I ever get at work is a virtual machine...
2011-05-10, 5:11 PM #13
Wouldn't a laser only follow the curvature of the event horizon of a black hole?
2011-05-10, 10:29 PM #14
actualy, it wi]ould follow the curvature of the swatzchild radius, the point at which the speed required to maintain a stable orbit is equal to the speed of light. (iirc the term correctly)
Snail racing: (500 posts per line)------@%
2011-05-10, 11:14 PM #15
Schwartzschild radius. /r/askscience actually had an interesting conversation on light orbiting blackholes about a monthish ago.
omnia mea mecum porto
2011-05-11, 3:46 AM #16
I like this thread and then I hated it.
"Guns don't kill people, I kill people."
2011-05-11, 3:46 PM #17
At first blush, it looks like the Schwartzschild radius is the event horizon.

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