Actually, I said "hypothetically speaking." However Air Pressure is most certainly NOT a phenomenon. Additonally, I DID address this in a previous post, I wasn't avoiding it...though InsanityDecends and James Bond have failed to rebuttle on a number of my statements/claims. Can I assume a concession on their part for those items?
There's just one problem with that. Objects in space traveling at a constant velocity with NO RESISTANCE DUE TO FRICTION still have "force" (at least, "force" as described by Newton because the object has "Knetic Energy" also as described by Newton). Keep in mind that the value of a Newton is constituted by Newtons Second law, which is solely based around the principle of the acceleration of an object being proportional to the net force acted apon it. It does NOT however, give us the "Force" in kinetic energy, that is to say, the "Force" that will act apon another object if it gets in our observed objects way.
Understandibly, there is a lot that has to be "modified" to takes these principles into account.
I swore to myself I wasn't going to use google, but while desperately trying to prove your claim (by trying to find a true vacuum chamber at sea level), I ran accross this interesting little tid bit:
http://www.abcfield.force9.co.uk/VTA/gravity.htm
I suppose my hypothetical analysis isn't totally ungrounded...
And please, do not continue to try and insult my inteligence with such comments as: "we'll use a simple word problem. i hope youv'e done them before?"
It's totally uncalled for and only serves to make you appear immature.
I'm glad we finally agree on something.
Strictly speaking, it doesn't. That example had nothing to do with "Force." It was oriented towards the discussion of Constant Acceleration vs Constant Velocity.
The problem is between what is being observed and what is actually happening. Again, an event can only be truly observed from the same inertial frame as the event. In this case, our 'event' is the engine. As you said, there are "forces" acting against it which DOES NOT cause A = 0, but rather causes the resultant of the two forces (where "force" is an abstract of Newtons Second law) working against each other to create an "observed" A of 0. Get the difference? The thing is, that's NOT what I'm concerned with. The point is, as far as the engine knows, it's having to continually do work as if it was constantly accelerating in a void. You must use that methodoligy of figuring that out before you can make the above determination [of forces working against each other to bring an observed equalibrium (of accereration) of 0].
The idea is to start at the smallest evident level of physics occuring in the problem and work your way out. Einstein tried to look at the larger picture and then work his way inward. It doesn't work out right when you do it that way. I know this first hand from taking events described in Relativity and working them both ways. I too got the same results Einstein did when working the problems that way. But I got a more rational solution when working the problems from the other direction.
Have you ever noticed when this occurs? Rarely do I ever respond to anything over the weekend. By the time Monday rolls around, the thread is ussually on the second or third page, so yeah, I generally don't bother trying to revive it. I haven't seen anyone post any "proof" yet. Quoting (summerized or not) examples or text out of various physics books/papers does not constitute "proof." What I have yet to see, is a logical connection (that I can't disprove) connecting their claims with the fundamental basics of physics. My claims against Relativity stands (though it's far more complex then the mere scope of this thread which only skims the surface).
Yes, I have. Did you know that in Physics, more often then not, you can make a "realization" about your problem and never have to carry out an intergration? Just like the majority of 3-dimensional problems can actually be worked in 2-dimensions. It just requires thinking outside the scope of the problems.
[quote=James Bond]ever got excel to plot a graph, it can give you an equation that is a direct representation of the curve in mathematical form, using that formula and intergation (over dt) you can know anything you need to know.[/quote]
I have used
Maple on many occassions. I'm not sure what you're getting at here...
I think you have it backwards. I have addressed every point you guys have made. It has been you guys who have not addressed all of my points made in deffense of my previous points (after you guys attacked them).
You see Emon?
Did you know that they are actually two different classes of Muon's? That's right, they use a
Lab Muon's value for a
Cosmic Ray Muon. Such are the problems with much of the "Proofs" of Relativity. This despite the fact that a
Lab Muon has a rest mass of 0.757028. Now through that into the lovely equation presented on page 2 of this thread and tell me what the mass would be at 0.97c? I would think it would be kind of hard to test something that massive at those speeds and get an accurate decay rate, don't you think?
Also (from another muon experiment done using the traditional freefall method):
"Another source of error is related with a basic assumption of the experiment, it is assumed that the charge on the muon makes no difference on the lifetime. This assumption is true if the particle is in space. But in the presense of matter, a few quantum effects accent the erroneous assumption. First of all, there is an inherent unbalance of µ+and µ−. Exactly,µ+µ−= 1.14 ± .04. The true effect that makes a difference is executed when the muons enter thematter. Once at non-relativistic speeds, the negative muons have a chance of being capturedby the atoms in the scintillator. This capture is on the time scale of 10−14sec which makesit a fast enough interaction to effect muon lifetime. By allowing the muon to come to alower energy state through the interaction: µ−+ N → N∗+ νµ, a new pathway effectivelyshortens the lifetime. This is shown by the lifetime without the absorption mode: τ =1Γdecay compared to the lifetime with the aborption mode: τ =1Γdecay+Γabsorb. The addition term inthe denominator shortens the muon lifetime τ.Finally, the last source of error comes from the formation of muonium. When the free,non-relativistic positive muon captures a free electron, the electron emits photons as itfalls into the muon’s potential well. This interaction also happens on the time scale of10−14seconds. Thus, this fast effect can mimic the scintillation of an emitted electron afterthe decay of the muon at rest that is capturing the electron. This emission could give apremature stop signal in coincidence with a cosmic muon hitting the bottom scintillator,effectively shortening the [calculated] lifetime."
Farewell.