Alco
Monty Hall's Favorite Contestant
Posts: 760
Yes, that's what the percentage does [Correction thanks to BobTheMasher. I originally misread this post. Population Percentage is what was used in the majority of the headers, so it should be used for all of them for consistency. If you wanted to do Population density, you should break it down by city instead due to variances in density distribution across entire states]. So if we look at New Hampshire's murder rate of 1 and New York's murder rate of 4, what does that mean? Does that mean that it's more likely to be murdered in New York than New Hampshire? The answer is "No".
As of 2006, the population of these states were estimated at:
NH = 1,315,000
NY = 19,306,000
If we take the Murder rates above as:
NH = 1
NY = 4
Then we can find the Murder rate as a percentage of population using the formula:
(Murder Rate/Population)*100
We find that:
NH = 7.6e^-5% OR 0.000076%
NY = 2.1e^-5% OR 0.000021%
As you can see, while NY's murder rate looks alarming compared to NH's, you are actually more likely to be murdered in NH than NY.
Divorce Rate (Per 1,000 people):
NH = 3
NY = 3
Divorce by Percentage of Population:
[Corrected formula is (Divorce Rate/(Population/1,000))*100]
NH = 2.3e^-4% OR 0.00023% [Corrected = 0.23%]
NY = 1.5e^-5% OR 0.00002% [Corrected = 0.02%]
Theft Rate:
NH = 1892
NY = 1976
Theft by Percentage of Population
NH = 0.14%
NY = 0.01%
Though, I have to say that those divorce rates don't look right for those states. The murder rates don't look right either. I'll do some fact checking...
[edit]
Okay, the murder rate is accurate. The divorce rate is not. The divorce rate is per 1,000 people. So, I will correct the formula above to compensate.